Find Smallest and Largest Element in an Array

Logic:

• Initialise two variable largest and smallest with arr[0]
• Iterate over array

             - If current element is greater than largest, then assign current element to largest.

             - If current element is smaller than smallest, then assign current element to smallest.

• You will get smallest and largest element in the end.

class FindLargestSmallestNumberMain {

      public static void main(String[] args) {

      // array of 10 numbers

      int arr[] = new int[] { 2, 23, 76, 42, 100, 85, 96, 56 };

      // assign first element of an array to largest and smallest

      int smallest = arr[0];

      int largest = arr[0];

      for (int i = 1; i < arr.length; i++) {

            if (arr[i] > largest) {

                  largest = arr[i];

            }else if (arr[i] < smallest) {

                  smallest = arr[i];

            }

      }

      System.out.println("Smallest Number is : " + smallest);

      System.out.println("Largest Number is : " + largest);

      }

}

Output:

Smallest Number is : 2

Largest Number is : 100